Question

Solve the equation x3-1=0 using De Moivers rule.​

Answer 1

Answer:

${x}^{3} - {1}^{3} = 0 \\ \\ (x - 1)( {x}^{2} + x + 1) = 0 \\ \\ x = 1 \: ,\:w \: ,\: {w}^{2}$