Question

Solve the equations
32/x-y + 36/x+y. = 7
40/x-y. + 48/x+y. =9
Can anybody? plzz..

Answer 1

Answer:

Hii mate

steps of construction:

32/x-y+36/X+y=7

40/x-y+48/X+y=9

let 1/x-y=a,1/X+y=b

then

32a+36b=7...eq1

40a+48b=9...eq2

40xeq1 and. 32xeq2

1280a+1440b=280

1280a+1536b=288

Subtract EQ:1-2

1280a+1440b=280

1280a+1536b=288

- - -

________________

-96b=-8

b=-8/-96

b=1/12

__________________

sub b. in eq1

32a+36b=7

32a+36(1/12)=7

32a+3=7

32a=7-3

32a=4

a=4/32

a=1/8

then we know that a=1/x-y,b=1/X+y

1/8=1/x-y 1/12=1/X+y

8=x-y EQ(3) 12=X+y EQ(4)

then add eq1&2

x-y=8

x+y=12

+ +. +

_______

2x. =20

X=10

and b=2

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