Question

Solve the equations by the method of
elimination x+3y=6&2x-3y=12​

Answer 1

$\bf{\underline{Question:-}}$

Solve the equations by the method of

elimination x + 3y = 6 and 2x - 3y = 12.

$\bf{\underline{Given:-}}$

• X + 3y = 6 -----equ(¡)
• 2x - 3y = 12 ------eq(¡¡)

$\bf{\underline{Solution:-}}$

multiply eq (¡) by 2

we get,

→ 2x + 6y = 12

• now subtract both eq

→ 2x + 6y = 12

→ $\sf{\underline{ _-2x-_+ 3y=_-12}}$

→ 9y = 0

→ y = 0

• y = 0 substitiute in eq (¡)

→ x + 3y = 6

→ x +3 × 0 = 6

→ x=6

$\bf{\underline{Hence:-}}$

• X = 6
• Y = 0