Question

solve the equations
By transposition method =3(x+4)=27
By trial and error method=10x=40
By systematic method=5(y+1)=40​

Answer 1

Step-by-step explanation:

$3(x + 4) = 27 \\ 3x + 12 = 27 \\ 3x = 27 - 12 \ \\ 3x = 15 \\ x = \frac{15}{3 } \\ x = 5$

$10x = 40 \\ x = \frac{40}{10} \\ x = 4$

$5(y + 1) = 40 \\ 5y + 5 = 40 \\ 5y = 40 - 5 \\ 5y = 35 \\ y = \frac{35}{5 } \\ y = 7$

Answer 2

Step-by-step explanation:

3(X+4)=27

3X+12=27

SUBTRACTING 12 FROM BOTH SIDES

3X+12-12=27-12

3X=15

X=5

BY TRIAL AND ERROR

LET X BE 1

10*1=40

10 IS NOT EQUAL TO 40

LET X BE 2

10*2=40

20 IS NOT EQUAL TO 40........

THIS PROCESS WILL GO ON UNTIL X= 10

YOU WILL GET YOUR ANSWER

BY SYSTEMATIC METHOD

5(Y+1)=40

5Y+5=40

5Y=35

Y=7

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