Math, asked by abhinavchandel9990, 1 year ago

Solve the equations:
(i) 5x = 3x + 24;
(ii) 8t + 5 = 2t − 31;
(iii) 7x − 10 = 4x + 11;
(iv) 4z + 3 = 6 + 2z;
(v) 2x − 1 = 14 − x;
(vi) 6x + 1 = 3(x − 1) + 7;
(vii) \frac{2x}{5} -\frac{3}{2} =\frac{x}{2} + 1
(viii) \frac{x-3}{5} -2 =\frac{2x}{5}
(ix) 3(x + 1) = 12 + 4(x − 1);
(x) 2x − 5 = 3(x − 5);
(xi) 6(1 − 4x) + 7(2 + 5x) = 53;
(xii) 3(x+6)+2(x+3) = 64;
(xiii) \frac{2m}{3} +8 =\frac{m}{2} -1
(xiv) \frac{3}{4} (x-1)= x-3 .

Answers

Answered by namith99
2
2x=24
therefore X=24/2 =12
Answered by muhammadshahab97
1
1 5x=3x + 24
5x-3x= 24
2x=24
x=24÷2
x=12 Ans

2 8t + 5 = 2t-31
8t- 2t =-31-5
6t =26
t=26÷6
t=13÷3 And

3 7x-10=4x+11
7x-4x=11+10
3x=21
x=21÷3
x=7 Ans

4 4z+3=6+2z
4z-2z=6-3
2z=3
z=3÷2






muhammadshahab97: I will answer your question latter
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