Question

Solve the equations: (i) x² - (x-1)² = 2; (ii) (x-4)(2x+3)=2x²​

Answer 1

$(i) {x}^{2} - {(x - 1)}^{2} = 2 \\ {x }^{2} - ( {x}^{2} - 2x + 1) = 2$

Since,

${(x - y)}^{2} = {x}^{2} - 2xy + {y}^{2}$

${x}^{2} - {x}^{2} + 2x - 1 = 2 \\ 2x - 1 = 2 \\ 2x = 2 + 1 \\ 2x = 3 \\ <strong>x = \frac{3}{2}</strong>$

Hope this will be helpful.

Answer 2

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