Question

solve
the equdratic equation x² + 3x= 10 by
factorization method.​

Answer 1

$= {x}^{2} + 3x - 10 = 0 \\ = {x}^{2} + 5x - 2x - 10 = 0\\ = x(x + 5) - 2(x + 5) = 0\\ = (x + 5)(x - 2) = 0$

.°. x+5 = 0,

x = -5.

.°. x-2 = 0,

x = 2.

The value of x = -5 or x = 2.

Answer 2

Step-by-step explanation:

x² +3x -10

x²+X (5-2)-10

x²+ 5x -2x -10

x(X+5) -2(X+5)

(X+5)(x-2)

if X+5=0

then X= -5

if X-2=0

then X= 2

ANS = -5 , 2

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