Question

solve the equetion 2x^2 -5x+3=0 the method of competing the square​

Answer 1

2x^2 - 5x + 3 = 0

=> 2x^2 / 2 - 5x /2 + 3/2 = 0

( Dividing by 2 )

=> x^2 - 5x/2 + 3/2 = 0

=> x^2 - 2(x)(5/4) + (5/4)^2 - (5/4)^2 + 3/2

=> (x-5/4)^2 = 25/16 - 3/2 = 1/16 = (1/4)^2

Comparing both sides , we get

x - 5/4 =+/- 1/4

=> x = 5/4 + 1/4 = 6/4 = 3/2

=> x = 3/2

Now , x = 5/4 - 1/4 = 4/4 = 1

=> x = 1

Hence roots of x are 3/2 , 1