solve the factorise (l+m)(l+m)-4lm
rakeshmohata:
( l - m) ² is ur answer
plz solve it completely
(l +m) ² - 4lm
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this is a my answer please bnlst
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Hey friend, Harish here.
Here is your answer:
(l+m)(l+m) - 4lm = (l+m)² - 4lm
We know that ,
(a + b)² = a² + b² + 2ab.
So,
(l + m)² - 4lm = l² + m² + 2lm - 4lm
⇒ l² + m² - 2lm = (l - m)²
Therefore (l+m)(l+m) -4lm = (l-m)²
_______________________________________________
Hope my answer is helpful to you.
Here is your answer:
(l+m)(l+m) - 4lm = (l+m)² - 4lm
We know that ,
(a + b)² = a² + b² + 2ab.
So,
(l + m)² - 4lm = l² + m² + 2lm - 4lm
⇒ l² + m² - 2lm = (l - m)²
Therefore (l+m)(l+m) -4lm = (l-m)²
_______________________________________________
Hope my answer is helpful to you.
Mark as brainiest if u like my answer
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