Solve the first question
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PLEASE MARK AS BRAINLIEST
PLEASE MARK AS BRAINLIEST
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We have in triangle abe g
<aeb = 90 degree (given)
<b = 60 degree (given)
AB = 8cm
Ae/ab = sin 60
Ae/ab = root3/2
Ae/8 = root 3/2
Ae = 8 root 3/2. = 4 root 3
Now, by Pythagoras theorem,
Ab^2 = ae^2 + be^2
64 = 48 + be^2
be^2 = 16
➡️be = 4cm.......
Therefore, ec = bc - be
ec = 25 - 4 = 21cm
Now in triangle aec -
Ac^2 = ae^2 + ec^2......(i)
(finding ae :
Ae^2 = ab^2 - be^2
Ae ^2= 64 - 16
Ae^2 = 48
Ae = 4 root 3.cm)
Putting ae = 4 root 3 in i -
Ac^2 = 48 + 441
Ac^2 = 489
Ac^2
➡️Ac = 22.11 cm
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