Question

Solve the following ⬆⬆⬆​

Answer 1

hope this helps you☺️☺️☺️

Answer 2

$\huge\star\underline\mathfrak\green{Hello \: Dear}\star$ $\huge{\mathfrak{\blue{Answer:-}}}$

area of semi- circle =

$\frac{\pi}{2} \times {r}^{2} = \frac{\pi}{2} \times ( \frac{9}{2} ) {}^{2} = \frac{81}{16}\pi \: {cm}^{2} \\ area \: of \: region \: (a) \: = \pi {r}^{2} = \pi( \frac{9}{4} )^{2} = \frac{81}{16}\pi \: {cm }^{2} \\ area \: of \: region \: (b \: + c) \: = \pi( \frac{3}{2} ) {}^{2} = \frac{9}{4}\pi \: {cm}^{2} \\ area \: of \: region \: (d) = \frac{\pi}{2}( \frac{3}{2}) {}^{2} = \frac{9}{8}\pi \: cm^{2} \\ area \: of \: shaded \: region \: = \frac{81}{8}\pi + \frac{81}{16}\pi - \frac{9}{4}\pi + \frac{9}{8}\pi \\ \\ = \pi( \frac{162 - 81 - 36 + 18}{16} ) \\ = \frac{63}{16}\pi \\ = \frac{63}{16} \times \frac{22}{7} \\ = \frac{99}{8} {cm}^{2}$