Question

Solve the following​

Answer 1

[(y – (4 – 3y))/ (2y – (3 + 4y))] = 1/5

[(y – (4 – 3y))/ (2y – (3 + 4y))] = 1/5(y – 4 + 3y)/ (2y – 3 – 4y) = 1/5

[(y – (4 – 3y))/ (2y – (3 + 4y))] = 1/5(y – 4 + 3y)/ (2y – 3 – 4y) = 1/5(-4y – 4)/ (2y – 3) = 1/5

by cross multiplication

5 × (-4y – 4) = 1 × (2y – 3)

20y – 20 = 2y

20y – 2y = 20 – 3

22 y = 17

y = 17/22

hope it helps

nd if it's helps pls do mark me as a brainleist

HAVE A GOOD DAY