solve the following
2x+3y=100;
5x+6y=200
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Answer:
x = 0 , y = 100/3
Step-by-step explanation:
2x + 3y = 100 (i)
5x + 6y = 200 (ii)
cofficient are not same so multiple (i) by 5 and (ii) by 2
5 ( 2x + 3y = 100 )
2 ( 5x + 6y = 200 )
10x + 15y = 500 (iii)
10x + 12y = 400 (iv)
when we subtract (iv) from (iii) then we get
3y = 100
y = 100/3
now put y value in (i) to find value of x
2x + 3*100/3 = 100
2x = 0
x = 0/2 = 0
✌️Hope this helps you ✌️
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