Solve the following : 3y-8/2y=1
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Answer:
taking LCM:-
6y^2-8
------------ = 1
2y
6y^2-8=2y
6y^2-2y-8=0
6y^2-6y+8y-8
6y(y-1)+8(y-1)
(6y+8) (y-1)
y=-8/6. or y=1
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