solve the following
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hope this will help u and welcome
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Solution
Given :-
- (x + 1) & (x + 2) are roots of this Equation (x³ + 3x² - 2px + q = 0
Find :-
- Value of x & y.
Explanation
We know,
If (x + 1) & (x + 2) be are roots of this Equation.
that mean x = -1 & x = -2. satisfied in this Equation.
Case 1.
- When, x = -1.
==> (-1)³ + 3(-1)² - 2×p(-1) + q = 0
==> -1 + 3 + 2p + q = 0
==> 2p + q = -2 ___________(1)
Case 2.
- When , x = -2,
==> (-2)³ + 3(-2)² - 2p(-2) + q = 0
==> -8 + 12 + 4p + q = 0
==> 4p + q = -4___________(2)
Subtract equ(1) & equ(2)
==> 2p - 4p = 2
==> -2p = 2
==> p = -2/2
==> p = -1
keep in equ(2)
==> 4(-1) + q = -4
==> -4 + q = -4
==> q = 0.
Hence
- value of p = = -1 .
- Value of q = 0
________________________
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