Question

solve the following 4x^2-2x+12/8x​

Answer 1

Step-by-step explanation:

42−2+128⋅

4x^{2}-2x+\frac{12}{8} \cdot x4x2−2x+812⋅x

Simplify

1

Divide the numbers

42−2+128⋅

4x^{2}-2x+{\color{#c92786}{\frac{12}{8}}} \cdot x4x2−2x+812⋅x

42−2+32

4x^{2}-2x+{\color{#c92786}{\frac{3}{2}}}x4x2−2x+23x

2

Combine multiplied terms into a single fraction

42−2+32

4x^{2}-2x+\frac{3}{2}x4x2−2x+23x

42−2+32

4x^{2}-2x+\frac{3x}{2}4x2−2x+23x

Solution

42−2+32