solve the following 4x+3y=-6xy and 2x-y=12xy
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Step-by-step explanation:
2x)^3 + (3y)^3 = (2x + 3y) (4x ^2 - 6xy + 9y^2) = 13 (4x^2 + 9y^2 - 36) Squaring 2x + 3y = 13. We get, 4x^2 + 9y^2 + 12xy = ...
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