Question

Solve the following
(5/4)^-2÷(2/3)^4

Answer 1

Answer:

${ \frac{5}{4} }^{ - 2} \div { \frac{2}{3} }^{4}$

${ \frac{4}{5} }^{2} \div { \frac{2}{3} }^{4}$

$\frac{16}{25} \div \frac{16}{81}$

$reciprocal \: of \: \frac{16}{81} \: is \: \frac{81}{16}$

$\frac{16}{25} \times \frac{81}{16}$

$cancellation$

$\frac{81}{25} = 3.24$

Answer 2

$\bf{\underline{\underline{\bigstar\bigstar\: Equation : }}}$

$\:$

• $\footnotesize{ \Big(\dfrac{5}{4}\Big)^{-2} \div \Big(\dfrac{2}{3}\Big)^{4} }$

$\:$

$\bf{\underline{\underline{\bigstar\bigstar\: Formula \: used : }}}$

$\:$

• $\footnotesize{ a^{-1} = \dfrac{1}{a} }$

$\:$

$\bf{\underline{\underline{\bigstar\bigstar\: Solution : }}}$

$\:$

$\footnotesize{ \Big(\dfrac{5}{4}\Big)^{-2} \div \Big(\dfrac{2}{3}\Big)^{4} }$

$\footnotesize{= \Big(\dfrac{4}{5}\Big)^{2} \div \Big(\dfrac{2}{3}\Big)^{4} }$

$\footnotesize{= \dfrac{16}{25} \div \dfrac{16}{81}}$

$\footnotesize{= \dfrac{16}{25} \times \dfrac{81}{16}}$

$\footnotesize{= \dfrac{81}{25} }$

$\:$

$\bold{\bigstar\: Answer = \dfrac{81}{25} }$