Math, asked by study9690, 1 year ago

solve the following​

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Answered by Anonymous
0

Answer:

-75y/x²

Step-by-step explanation:

When two simultaneous equations - a₁x+b₁y+c₁=0 and a₂x+b₂y+c₂=0 then if they had a unique solution then a₁/a₂≠b₁/b₂

So, here a₁ = 5 , a₂ = x and b₁ = -k , b₂ = 15

So, 5/x ≠ -k/15

So, k ≠ -75y/x²

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