English, asked by swanandigunjal009, 16 days ago

Solve the following activities.​

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Answered by harshmathia
0

2))

1)) 2(1) x - 2(1/2)

2-1

=1

3)) Let A(2,k) and B(-4,2) be two points and slope m=1/2.

Slope=y2-y1/x2-x1. 1/2=2-k/-4-2 [y1=k,y2=2,x1=2,x2=-4,m=1/2] ⇒ -(4+2)=2(2-k) -6=4-2k. 2k=10.

⇒k=5. Hope it helps you.

4)) ◆ Answer -

CSA = 1056 sq.cm

● Explanation -

# Given -

d = 14 cm

h = 24 cm

# Solution -

Curved surface area of cylinder is -

CSA = 2 × π × r × h

CSA = 2 × π × d/2 × h

CSA = π × d × h

CSA = 22/7 × 14 × 24

CSA = 1056 sq.cm

Hence, the curved surface area of cylinder is 1056 sq.cm.

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