Solve the following activities.
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2))
1)) 2(1) x - 2(1/2)
2-1
=1
3)) Let A(2,k) and B(-4,2) be two points and slope m=1/2.
Slope=y2-y1/x2-x1. 1/2=2-k/-4-2 [y1=k,y2=2,x1=2,x2=-4,m=1/2] ⇒ -(4+2)=2(2-k) -6=4-2k. 2k=10.
⇒k=5. Hope it helps you.
4)) ◆ Answer -
CSA = 1056 sq.cm
● Explanation -
# Given -
d = 14 cm
h = 24 cm
# Solution -
Curved surface area of cylinder is -
CSA = 2 × π × r × h
CSA = 2 × π × d/2 × h
CSA = π × d × h
CSA = 22/7 × 14 × 24
CSA = 1056 sq.cm
Hence, the curved surface area of cylinder is 1056 sq.cm.
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