Question

Solve the following best answer will be marked as brainliest......
It's urgent so no spamming!!!

Answer 1

sorry dear I am only able to give only 1st question answer sorry.......

Answer 2

HeY MaTe HeRe Is YoUr AnSwEr ❤

$1) \: = > \: {x}^{3} + {y}^{3} + {z}^{3} - 3xyz = (x + y + z) \: ( {x}^{2} + {y}^{2} + {z}^{2} - xy - yz - zx) \\ = > if \: x + y + z = 0 \: \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: then \\ = > {x}^{3} + {y}^{3} + {z}^{3} - 3xyz = 0 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: or \\ = > {x}^{ 3} + {y}^{3} + {z}^{3} = 3xyz \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: here \\ = > a + 2b + 3c = 0 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: so \\ = > ( {a})^{3} + ( {2b})^{3} + ({3c})^{3} = 3 \times a \times 2b \times 3c \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: or \\ = > {a}^{3} + {8b}^{3} + {27c}^{3} = 18abc \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: proved$

$\\ 2) \: = > {8x}^{3} - {27y}^{3} - 90xy + 125 \: \: \: |2x - 3y - 5| \\ = > ( {2x})^{3} - ( {3y})^{3} - 3(2x)(3y) \: \: |2x - 3y| \\ = > ( {3y - 5})^{3} - ( {3y})^{3} - 18xy \: \: |3y - 5 - 3y| \\ = > {27y}^{3} - 125 - {27y}^{3} + 90xy \\ \: \: \: \: \: \: \: \: \: \: \: \: {27y}^{3} \: wil \: be \: canceled \\ = > 90xy - 125$

sorry dude coz I can't able to do the last question but which questions I answered will definitely help u out.

please mark me as brainliest ❤