Math, asked by rusheelsablep6yz03, 1 year ago

Solve the following by any suitable method

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Answered by abhi569
2
8x - 3y  = 5xy   ----1equation 
6x - 5y = -2xy   -----2equation 

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[ 8x - 3y = 5xy  ]      ×   5
[ 6x - 5y = -2xy ]      ×   3

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40x - 15y = 25xy   ---3equation 
18x - 15y = -6xy    ---4equation 

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Subtracting eq(4) from eq(3)

40x - 15y = 25xy 
18x - 15y = -6xy 
-     +           + 
_______________
22x   + 0  = 31 xy 
_______________

22x = 31 xy 

22 = 31 y 

22/31 = y 

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Putting the value of y in 1equation, 

8x - 3y = 5xy 

8(22/31) - 3x = 5(22/31)x 

(176/31) = 110x/31 + 3x 

176/31 = 203x/31 

176 = 203x

176/203 = x

rusheelsablep6yz03: thank you
abhi569: welcome
rusheelsablep6yz03: I think it's wrong
rusheelsablep6yz03: because
rusheelsablep6yz03: when you put y in 1
rusheelsablep6yz03: U shifted - 3x to right without changing the sign
abhi569: Hmmm
abhi569: Hmm wait bro
abhi569: Correct
abhi569: (-:
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