Solve the following by putting the values of the trigonmentric ratios of standard angles
i). Sin 30° × cos 30°
ii). Cos 45° × tan 60°
iii). Cot 60° × cot 30°
iv). tan 45° × cosec 30°
v). Sin 60° × cosec 60°
vi). tan 30° × sec 30°
vii). Cosec 45° × cos 30°
viii). Sec 45° × sin 45°
ix). Cosec 90° × cos 90°
x). tan 0° × sin 90°
xi). sin 45° / cos 60°
xii). Cosec 60° / sin 45°
Answers
Answered by
2
Answer:
- √3/4
- √6/2
- 1
- 2
- 1
- 2/3
- √6/2
- 1
- 0
- 0
- √2/4
- √6/3
step by step explanation:
- sin30° × cos30° = 1/2 × √3/2 =√3/4
- cos45° × tan60° = 1/√2 × √3 =√6/2
- cot60° × cot30° = 1/√3 × √3 =1
- tan45° × cosec30° = 1 × 2 =2
- sin60° × cosec60° = √3/2 × 2√3 =1
- tan30° × sec30° = 1/√3 × 2√3 =2/3
- cosec45° × cos30° = √2 × √3/2 =√6/2
- sec45° × sin45° = √2 × 1/√2 =1
- cosec90° × cos90° = 1 × 0 =0
- tan0° × sin90° = 0 × 1 =0
- sin45° × cos60° = 1/√2 × 1/2 =√2/4
- cosec60° × sin45° = 2/√3 × 1/√2 =√6/3
!! Hope So It Helps You !!
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