Question

solve the following by substitution method
1.3x-4y=0
4x+3y =5
2.√x+√3y=1.3
√3x +√8y=0

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Answer 1

1.) 3x-4y=0;4x+3y =5

sol:

3x-4y=0---------(1)

4x+3y =5---------(2)

multiple by 4 for equ (1)

multiple by 3 for equ (2)

12x-16y=0

12x+9y=15

-7y=15

y=-15/7

y=-15/7 substitute for equ (1)

3x-4y=0

3x-4(-15/7) =0

3x+(60/7) =0

3x+8.57=0

3x=8.57

x=8.57/3

x=2.8

y=-2.14

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