Question

Solve the following by transposition method and verify the solution. y/8=3y/4–10​

Answer 1

Answer:

• y = 16

Explanation:

Given equation,

$\rm \implies \: \dfrac{y}{8} = \dfrac{3y}{4} - 10$

Transposing y/8 to L.H.S. and -10 to R.H.S. as follows :-

$\rm \implies \: 10 = \dfrac{3y}{4} - \dfrac{y}{8}$

Solving further,

$\rm \implies \: 10 = \dfrac{6y - y}{8}$

$\rm \implies \: 10 = \dfrac{5y}{8}$

Transposing again,

$\rm \implies \: \dfrac{8 \ast 10}{5} =y$

$\rm \implies \: \dfrac{80}{5} =y$

$\rm \implies \: 16 =y$

∴ The value of ‘y’ is 16.

Verification:

Substituting the value ‘y’ :-

$\rm \implies \: \dfrac{y}{8} = \dfrac{3y}{4} - 10$

$\rm \implies \: \dfrac{16}{8} = \dfrac{3(16)}{4} - 10$

$\rm \implies \: 2 = {3(4)}{} - 10$

$\rm \implies \: 2 = 12 - 10$

$\rm \implies \: 2 = 2$

Hence verified!!

Answer 2

Step-by-step explanation:

Solving:

$\frac{y}{8} = \frac{3y}{4} - 10 \\ 10 = \frac{3y}{4} - \frac{y}{8} \\ 10 = \frac{6y - y}{8} \\ 10 = \frac{5y}{8} \\ 10 \times 8 = 5y \\ 80 = 5y \\5y = 80 \\ y = \frac{80}{5} \\ y = 16$

Verification:

$\frac{y}{8} = \frac{3y}{4} - 10 \\ \frac{16}{8} = \frac{3 \times 16}{4} - 10 \\ 2 = 3 \times 4 - 10 \\ 2 = 12 - 10 \\ 2 = 2 \\ L.H.S= R.H.S$