Question

solve the following equation
1. 5(x+1)=3(x-2)​

Answer 1

$\large\sf\underline{Question}$

• $\sf\:5(x+1)=3(x-2)$

$\large\sf\underline{Solution}$

$\sf➪\:5(x+1)=3(x-2)$

$\sf➪\:5x+5=3x-6$

$\sf➪\:5x-3x=-6-5$

$\sf➪\:2x=-11$

$\sf➪\:x=\frac{-11}{2}$

$\sf➪\:x=-0.181$

• Thnku ❣

Answer 2

Given :

• $\sf{5(x+1)=3(x-2)}$

Solution :

$\implies\sf{5(x+1)=3(x-2)}$

$\implies\sf{5x+5=3x-6}$

$\implies\sf{5x-3x=-6-5}$

$\implies\displaystyle\sf{2x = -11}$

$\boxed{\boxed{\displaystyle {\sf{x = \frac{-11}{2}}}}}$

Verification :

$\implies\displaystyle{5\[\left(\frac{-11}{2}+1\right)\]= 3\[\left(\frac{-11}{2}-2\right)\]}$

$\implies\displaystyle{5\[\left(\frac{-11+2}{2}\right)\]= 3\[\left(\frac{-11-4}{2}\right)\]}$

$\implies \displaystyle{5\[\left(\frac{-13}{2}\right)\]= 3\[\left(\frac{-15}{2}\right)\]}$

$\implies \displaystyle{\frac{-45}{2}=\frac{-45}{2}}$

$\underline {\sf{Hence\:Verified}}$

Required Answer :

The solution of the given linear equation in one variable is $\boxed{\displaystyle{\sf{x=\frac{-11}{2}}}}$