Question

Solve the following equation : 1a²+2a=3

Answer 1

${a}^{2} + 2a - 3 = 0 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 3 = 3 \times 1 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 2 = 3 - 1 \\ {a}^{2} + 3a - a - 3 \\ a(a + 3) - 1(a + 3) \\ (a - 1)(a + 3) = 0 \\ therefore \: \: \: \\ a - 1 = 0 \: or \: a + 3 = 0 \\ a = 1 \: or \: a = - 3 \: are \: the \: roots$

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Answer 2

1a²+2a−3=0

3=3×1

2=3−1

a

2

+3a−a−3

a(a+3)−1(a+3)

(a−1)(a+3)=0

therefore

a−1=+3=0

a=1ora=−3