Question

Solve the following equation.

(-2)^2y = 64

Answer 1

Answer:

$\huge\bigstar\huge\tt\underline\red{ᴀɴsᴡᴇʀ }\bigstar$

${( - 2)}^{2y} = 64$

${( - 2)}^{2y} = {(-2)}^{6}$

$2y = 6$

$y = 3$

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Answer 2

Answer:

we will take 2y = 6 because denominator is same -2