solve the following equation 3x²+5x-12=0
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given 3x²+5x-12=0
Step-by-step explanation:
AC = 3*12 =-36
which differs by B = 5
The pair 9,-4 works
Use this pair to split the middle term, then factor
by grouping:
0=3x²+5x-12
(3x²+9x)+(-4x-12)
3x(x+3)-3(x+3)
(3x-3)+(x+3)
3x-3=0 , x+3=0
3x=3 , x=-3
x=3/3 , x=-3
x=1 and -3
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