Math, asked by rajeshmutha007, 1 month ago

solve the following equation​

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Answers

Answered by smosan75
5

QUESTION:

 {\orange{\frac{1 - x}{6}  +  \frac{2x}{3}  -  \frac{1 - 7x}{4}  = 6 \frac{2}{3} }}

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SOLUTION:

 \frac{1 - x}{6}  +  \frac{2x}{3}  -  \frac{1 - 7x}{4}  = 6 \frac{2}{3}

 \frac{2(1 - x) + 4(2x) - 3(1 - 7x)}{12}  =  \frac{20}{3}

2 - 2x + 8x - 3 + 21x =  \frac{20}{3}  \times 12

27x - 1 = 80

27x = 80 + 1

27x = 81

x =  \frac{81}{27}

{\blue{x = 3}}

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{\large{\mathcal{\red{Have \:  a \:  nice \:  day  \: ahead}}}}

Answered by GraceS
1

\sf\huge\bold\pink{Answer:}

 \\ 1−x+32x−41−7x=632 \\ \frac{2(1 - x) + 4(2x) - 3(1 - 7x)}{12} = \frac{20}{3}122(1−x)+4(2x)−3(1−7x)=320 \\ 2 - 2x + 8x - 3 + 21x = \frac{20}{3} \times 122−2x+8x−3+21x=320×12 \\ 27x - 1 = 8027x−1=80 \\ 27x = 80 + 127x=80+1 \\ 27x = 8127x=81 \\ x = \frac{81}{27}x=2781 \\ {\blue{x = 3}}

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