Question

solve the following equation:6x+13/2=19​

Answer 1

In accordance with the information provided in the question,

We have find the value of the supplied expression in the above question.

Given the data in question :6x+13/2=19​

balancing the equation and multiplication of 2  is cross multiplication of 19 and 6x

$6x\times2+13=19\times2\\=12x+13=38$

Hence, for solving the above equation, we will solve it by separating the like terms at one side.

So, we will shift 13 from LHS to RHS,

So, we will get it as,

$=12x+13=38\\=12x=38-13\\=12x=25\\x=\frac{25}{12} \\x=2.0833$

Hence the required value will be $x=2.0833$

Answer 2

$6x + \frac{13}{2} = 19$

$6x = 19 - \frac{13}{2}$

$6x = \frac{19}{1} - \frac{13}{2}$

$6x = \frac{38 - 13}{2}$

$6x \times 2 = 25$

$12x = 25$

$x = \frac{25}{12}$