Question

solve the following equation
9y^4+20=29y^2

Answer 1

Answer:

Step-by-step explanation:

9y^4 + 20 - 29y^2 = 0

9y^4 - 29y^2 + 20 = 0

9y^4 - 20y^2 - 9y^2 + 20 = 0

y^2(9y^2 - 20) -1(9y^2 - 20) = 0

(9y^2 - 20)(y^2 - 1) = 0

then

9y^2 - 20 = 0

9y^2 = 20

y^2 = 20/9

y = √(20/9)   ------------------ (i)

again

y^2 - 1 = 0

y^2 = 1

y = √1

y = 1  -----------------------(ii)

Answer 2

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