Question

solve the following equation
a)(2x+3)/(2x-1 ) = 3
b)5y-3=10
c)z/5+(z+2)/3= 2/3
d)2(2w+3) = 3w+7
e)3/(p+8)=4/(p-6)​

Answer 1

Step-by-step explanation:

a) cross multiply

So it becomes 2x+3 = 3(2x-1)

which is the same as 2x+3 = 6x-3

now transpose the numerical to Lhs and the variables to the Rhs.

→3+3 = 6x-2x

→6= 4x

→x =6/4 or 3/2