solve the following equation and check the results: 2x+4/5x=8
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2x+4/5x=8
4/5x=8-2x
4=5x(8-2x)
4=40x-10x^2
it gives equation
-10x^2+40x-4=0
in this equation a=-10,b=40,c=-4
=-b+-√b^2-4ac/2a
=-40+-√40^2-4×(-10)×(-4)/2×(-10)
=-40+-√1600-160/-20
=40+-√1440/-20
first zeroes will be
=40+√1440/-20
and second will be
=40-√1440/-20!!!!!!!
4/5x=8-2x
4=5x(8-2x)
4=40x-10x^2
it gives equation
-10x^2+40x-4=0
in this equation a=-10,b=40,c=-4
=-b+-√b^2-4ac/2a
=-40+-√40^2-4×(-10)×(-4)/2×(-10)
=-40+-√1600-160/-20
=40+-√1440/-20
first zeroes will be
=40+√1440/-20
and second will be
=40-√1440/-20!!!!!!!
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