Solve the following equation and represent it graphically.
3(2x-1) + 2(3x-1) = 51 – 5(x+1)
Answers
EXPLANATION.
Equation and represent it graphically.
⇒ 3(2x - 1) + 2(3x - 1) = 51 - 5(x + 1).
⇒ 6x - 3 + 6x - 2 = 51 - 5x - 5.
⇒ 12x - 5 = 46 - 5x.
⇒ 12x + 5x = 46 + 5.
⇒ 17x = 51.
⇒ x = 3.
Their Co-ordinates = (3,0).
MORE INFORMATION.
Graph of inverse trigonometric functions.
(1) =y = Sin⁻¹(x).
Domain = [-1,1].
Range = [-π/2,π/2].
Odd function.
(2) = y = cos⁻¹(x).
Domain = [-1,1].
Range = [0,π].
Neither even nor odd function.
(3) = y = tan⁻¹(x).
Domain = R.
Range = (-π/2,π/2).
Odd function.
(4) = y = cot⁻¹(x).
Domain = R.
Range = (0,π).
Neither even nor odd.
(5) = y = sec⁻¹(x).
Domain = (-∞,-1] ∪ [1,∞).
Range = [0,π] - {π/2}.
Neither even nor odd.
(6) = y = cosec⁻¹(x).
Domain = (-∞,-1] ∪ [1,∞).
Range = [-π/2,π/2] - {0}.
Odd function.
(7) = y = sin⁻¹(sin(x)).
(8) = y = cos⁻¹(cos(x)).
(9) = y = tan⁻¹(tan(x)).
7,8,9 these are represented on graph.
Note = All inverse trigonometric functions are monotonic.
Answer:
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Step-by-step explanation:
3(2X-1)+2(3X-1)=51-5(X+1)
=6X-3+6X-2=51-5X-5
=12X-5=46-5X
=12X+5X=46+5
=17X=51
=X=51/17
X=3