Question

solve the following equation and verify ur result ​

Answer 1

Answer:

x²-5x-6-x²-6-5x=3

-10x-12=3

-10x=15

x=-3

Answer 2

$(x-1)(x+6)-(x-2)(x-3)=3$

${x}^{2} + 6x - x - 6 - ( {x}^{2} - 3x - 2x + 6) = 3$

${x}^{2} + 5x - 6 - {x}^{2} + 3x + 2x - 6 = 3$

$5x + 5x - 6 - 6 = 3$

$10x - 12 = 3$

$10x = 3 + 12$

$10x = 15$

$x = \frac{15}{10}$

$\boxed{x = \frac{3}{2} }$

Verification:

$(x-1)(x+6)-(x-2)(x-3)=3$

$( \frac{3}{2} -1)( \frac{3}{2} +6)-( \frac{3}{2} -2)( \frac{3}{2} -3) = lhs$

$( \frac{3 - 2}{2} )( \frac{3 + 12}{2} ) - ( \frac{3 - 4}{2} )( \frac{3 - 6}{2} )$

$( \frac{1}{2} )( \frac{15}{2} ) - ( \frac{ - 1}{2} )( \frac{ - 3}{2} )$

$( \frac{15}{4} ) - ( \frac{3}{4} )$

$\frac{15 - 3}{4}$

$\frac{12}{4}$

$3 = rhs$

$hence \: verified$