solve the following equation by completing square 7x square-2x-1=0
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Answer:
Step-by-step explanation:
Two solutions were found :
x =(2-√32)/14=(1-2√ 2 )/7= -0.261
x =(2+√32)/14=(1+2√ 2 )/7= 0.547
Answered by
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solution:-
=> 7x²-2x-1=0
Solving 7x²-2x-1 = 0 by Completing The Square .
x²-(2/7)x-(1/7) = 0
x²-(2/7)x = 1/7
add both side 1/49
=> x²-(2/7)x+(1/49) = 8/49 ...............(1)
=> x²-(2/7)x+(1/49) = (x-(1/7))²..........(2)
from ( 1 ) and ( 2 )
(x-(1/7))² = 8/49
x = 1/7 + √ 8/49
has two solutions:
x = 1/7 + √ 8/49
or
x = 1/7 - √ 8/49
Note that √ 8/49 can be written as
√ 8 / √ 49 which is √ 8 / 7
I hope it helps you........
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