Question

solve the following equation by factorisation​

Answer 1

Solution:

$(x + 3)(x - 3) = 27 \\ \\ \implies \: x {}^{2} - 3 {}^{2} = 27 \\ \\ \implies \: x {}^{2} = 36 \\ \\ \implies \: x = \pm \sqrt{36} \\ \\ \implies \: x = - 6 \: or \: 6$

Here,

(x+3)(x-3) is of the form (a+b)(a-b)

=>a^2-b^2=x^2-3^2

The value of X are +6 and -6.

Answer 2

Answer :-) 6

$(x + 3)(x - 3) = 27$

By the Algebraic Property

${x}^{2} - {y}^{2} = (x + y)(x - y)$

So By using this property we get

${x}^{2} - {3}^{2} = 27$

${x}^{2} - 9 = 27$

${x}^{2} = 27 + 9$

${x}^{2} = 36$

$x = \sqrt{36}$

$x = 6$

So the value of x is 6

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