solve the following equation by factorisation
root 3 x^2+10x+7root3=0
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shrutijoshi:
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Here is your solution____________________
♦ √3x^2 + 10x + 7√3 = 0
=> √3x^2 + 3x + 7x + 7√3 = 0
=> √3x( x + √3) + 7 ( x + √3) = 0
=> (√3x + 7) ( x +√3) = 0
Now, (√3x + 7) = 0
=> √3x = -7
=> x = -7/√3
either x = -7/√3
or
( x + √3) = 0
=> x = -√3
Hence, -7/√3 and -√3 are the zeroes of the given equation.
Thanks☺
Here is your solution____________________
♦ √3x^2 + 10x + 7√3 = 0
=> √3x^2 + 3x + 7x + 7√3 = 0
=> √3x( x + √3) + 7 ( x + √3) = 0
=> (√3x + 7) ( x +√3) = 0
Now, (√3x + 7) = 0
=> √3x = -7
=> x = -7/√3
either x = -7/√3
or
( x + √3) = 0
=> x = -√3
Hence, -7/√3 and -√3 are the zeroes of the given equation.
Thanks☺
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