solve the following equation by Jacobi's method 10x + y + 2z = 13, 3x + 10y + z = 14, 2x + 3y + 10z = 15
Answers
Answer:
Step-by-step explanation:
(10x+y+2z=13)
(3x+10y+z=14)×2
subtract both outcomes become
4x-19y=-15 be equation 1st
another second one and third one
(3x+10y+z=14)×10
2x+3y+10z=15
subtract both then become
28x+97y=125
be second equation
from equation 1st and 2nd
28x+97y=125
(4x+19y=-15)×7
subtract both then become y=1
in equation 1st use y=1
finally become x=1
in given equation used value of x and y then become z=1 the value of x and y and z become 1 ...
Answer:
The Jacobi method is an iterative procedure for finding the answers to a strictly diagonally dominating system of linear equations in numerical linear algebra. A rough value is filled in after each diagonal element is solved. After then, the procedure is repeated until convergence.
Step-by-step explanation:
(10x+y+2z=13)
(3x+10y+z=14)×2
subtract both outcomes become
4x-19y=-15 by equation 1st
another second one and the third one
(3x+10y+z=14)×10
2x+3y+10z=15
subtract both then become
28x+97y=125
be second equation
from equations 1st and 2nd
28x+97y=125
(4x+19y=-15)×7
subtract both then become y=1
in equation 1st use y=1
finally, become x=1
in the given equation used values of x and y then become z=1 the value of x and y and z become 1 ...