Question

solve the following equation by substitution method 2 X + 3Y=4,x+2y=3​

Answer 1

Answer:

(i) x + y =5 and 2x –3y = 4

By elimination method

x + y =5 ... (i)

2x –3y = 4 ... (ii)

Multiplying equation (i) by (ii), we get

2x + 2y = 10 ... (iii)

2x –3y = 4 ... (ii)

Subtracting equation (ii) from equation (iii), we get

5y = 6

y = 6/5

Putting the value in equation (i), we get

x = 5 - (6/5) = 19/5

Hence, x = 19/5 and y = 6/5

By substitution methodx + y = 5 ... (i)

Subtracting y both side, we get

x = 5 - y ... (iv)

Putting the value of x in equation (ii) we get

2(5 – y) – 3y = 4

-5y = - 6

y = -6/-5 = 6/5

Putting the value of y in equation (iv) we get

x = 5 – 6/5

x = 19/5

Hence, x = 19/5 and y = 6/5 again

Step-by-step explanation:

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Answer 2

Answer:

find x form equation 2

x=3-2y

put this x into equation 1

2(3-2y)+3y=4

6-4y+3y=4

6-y=4

y=2

put y=2 in eq. 1

2x+6=4

2x=-2

x=-1