solve the following equation by substitution method 2 X + 3Y=4,x+2y=3
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Answer:
(i) x + y =5 and 2x –3y = 4
By elimination method
x + y =5 ... (i)
2x –3y = 4 ... (ii)
Multiplying equation (i) by (ii), we get
2x + 2y = 10 ... (iii)
2x –3y = 4 ... (ii)
Subtracting equation (ii) from equation (iii), we get
5y = 6
y = 6/5
Putting the value in equation (i), we get
x = 5 - (6/5) = 19/5
Hence, x = 19/5 and y = 6/5
By substitution methodx + y = 5 ... (i)
Subtracting y both side, we get
x = 5 - y ... (iv)
Putting the value of x in equation (ii) we get
2(5 – y) – 3y = 4
-5y = - 6
y = -6/-5 = 6/5
Putting the value of y in equation (iv) we get
x = 5 – 6/5
x = 19/5
Hence, x = 19/5 and y = 6/5 again
Step-by-step explanation:
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and the explanation in the answer
Answered by
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Answer:
find x form equation 2
x=3-2y
put this x into equation 1
2(3-2y)+3y=4
6-4y+3y=4
6-y=4
y=2
put y=2 in eq. 1
2x+6=4
2x=-2
x=-1
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