Question

Solve the following equation by transposing method and verify the result :


$\frac{y}{4} - \frac{1}{2} = \frac{y}{3} + 1$
​

Answer 1

Step-by-step explanation:

Given : Expression \frac{y-1}{3}-\frac{y-2}{4}=1

3

y−1

−

4

y−2

=1

To find : Solve the expression ?

Solution :

Expression \frac{y-1}{3}-\frac{y-2}{4}=1

3

y−1

−

4

y−2

=1

Take the LCM,

\frac{4(y-1)-3(y-2)}{12}=1

12

4(y−1)−3(y−2)

=1

4y-4-3y+6=124y−4−3y+6=12

y+2=12y+2=12

y=12-2y=12−2

y=10y=10