Math, asked by rudrakshm2010, 6 months ago

solve the following equation by trial and error method 3
+ 2 is equal to 17​

Answers

Answered by Mrvagh151
1

We use trial and error method,

We use trial and error method,5p+2=17

We use trial and error method,5p+2=17Put, p=0

We use trial and error method,5p+2=17Put, p=05(0)+2=17

We use trial and error method,5p+2=17Put, p=05(0)+2=17=> 2

We use trial and error method,5p+2=17Put, p=05(0)+2=17=> 2

We use trial and error method,5p+2=17Put, p=05(0)+2=17=> 2=17

We use trial and error method,5p+2=17Put, p=05(0)+2=17=> 2=17Put, p=1

We use trial and error method,5p+2=17Put, p=05(0)+2=17=> 2=17Put, p=15(1)+2=17

We use trial and error method,5p+2=17Put, p=05(0)+2=17=> 2=17Put, p=15(1)+2=17=> 7

We use trial and error method,5p+2=17Put, p=05(0)+2=17=> 2=17Put, p=15(1)+2=17=> 7

We use trial and error method,5p+2=17Put, p=05(0)+2=17=> 2=17Put, p=15(1)+2=17=> 7=17

We use trial and error method,5p+2=17Put, p=05(0)+2=17=> 2=17Put, p=15(1)+2=17=> 7=17Put, p=2

We use trial and error method,5p+2=17Put, p=05(0)+2=17=> 2=17Put, p=15(1)+2=17=> 7=17Put, p=25(2)+2=17

We use trial and error method,5p+2=17Put, p=05(0)+2=17=> 2=17Put, p=15(1)+2=17=> 7=17Put, p=25(2)+2=17=> 12

We use trial and error method,5p+2=17Put, p=05(0)+2=17=> 2=17Put, p=15(1)+2=17=> 7=17Put, p=25(2)+2=17=> 12

We use trial and error method,5p+2=17Put, p=05(0)+2=17=> 2=17Put, p=15(1)+2=17=> 7=17Put, p=25(2)+2=17=> 12=17

We use trial and error method,5p+2=17Put, p=05(0)+2=17=> 2=17Put, p=15(1)+2=17=> 7=17Put, p=25(2)+2=17=> 12=17Put, p=3

We use trial and error method,5p+2=17Put, p=05(0)+2=17=> 2=17Put, p=15(1)+2=17=> 7=17Put, p=25(2)+2=17=> 12=17Put, p=35(3)+2=17

We use trial and error method,5p+2=17Put, p=05(0)+2=17=> 2=17Put, p=15(1)+2=17=> 7=17Put, p=25(2)+2=17=> 12=17Put, p=35(3)+2=17=> 17=17

We use trial and error method,5p+2=17Put, p=05(0)+2=17=> 2=17Put, p=15(1)+2=17=> 7=17Put, p=25(2)+2=17=> 12=17Put, p=35(3)+2=17=> 17=17Hence p=3

ʜᴏᴘᴇ ɪᴛ ʜᴇʟᴘꜱ ʏᴏᴜ. ☺❤

Similar questions