Question

solve the following equation check your result in each case
$6(3x + 2) - 5(6x - 1) = 3 \\ \\ (x - 8) - 5(7x -6) + 9x$

Answer 1

$6(3x + 2) - 5(6x - 1) = 3 \\ 18x + 12 - 30x + 5 = 3 \\ - 12x + 17 = 3 \\ - 12x = 3 - 17 \\ x = \frac{ - 14}{ - 12} \\ x = \frac{7}{6} \\ verification - \\ put \: x = \frac{7}{6} \\ 6(3x + 2) - 5(6x - 1) = 3 \\ 6(3 \times \frac{7}{6} + 2) - 5(6 \times \frac{7}{6} - 1) = 3 \\ 6( \frac{7}{2} + 2) - 5(7 - 1) = 3 \\ 6( \frac{7 + 4}{2} ) - 5(7 - 1) = 3 \\ 6 \times \frac{11}{2} - 5 \times 6 = 3 \\ 33 - 30 = 3 \\ 3 = 3 \\ lhs = rhs$