Question

Solve the following equation for x and y by cross multiplication method
(ax-by)+(a+4b)=0
(bx+ay)+(b-4a)=0

Answer 1

Answer:

# hope so it will help you

please follow me

thanks my answer

Answer 2

Answer:

❤Hope it helps u Mark as brainliest if it helps u ❤

Step-by-step explanation:

ur ans is 2

The given system of equation may be written as

2(ax - by) + a + 4b = 0

So, 2ax - 2by + a + 4b ..............(i)

2(bx + ay) + b - 4a = 0

so, 2bx+2ay+b-4a=0................(ii)

compare (i) and (ii) with standard form, we get

a1 = 2a, b1 = -2b, c1 = a + 4b

a2 = 2b, b2 = 2a, c2 = b - 4a

By cross multiplication method

x−2b2+8ab−2a2−8abx−2b2+8ab−2a2−8ab =−y2ab−8a2−2ab−8b2=−y2ab−8a2−2ab−8b2 =14a2+4b2=14a2+4b2

x−2b2−2a2=−y−8a2−8b2=14a2+4b2x−2b2−2a2=−y−8a2−8b2=14a2+4b2

Now, x−2b2−2a2=14a2+4b2x−2b2−2a2=14a2+4b2

⇒x=−12⇒x=−12

And, −y−8a2−8b2=14a2+4b2−y−8a2−8b2=14a2+4b2

⇒y=2⇒y=2

Therefore, the solution of the given pair of equations are −12−12 and 2 respectively.