Question

Solve the following equation for x sin inverse 8/x + sin inverse 15/x =90 degree​

Answer 1

Answer:

must follow the instructions

Answer 2

Step-by-step explanation:

sin^-1(8/x) + sin^-1(15/x) = π/2

\text{but we know,}but we know,

\boxed{\boxed{\bold{sin^{-1}X+cos^{-1}X=\frac{\pi}{2}}}}

sin

−1

X+cos

−1

X=

2

π

so, Let sin^-1(15/x) = P

sinP = 15/x

then, cosP = √(x² - 225)/x

P = cos^-1{√(x² - 225)/x}

now, sin^-1(8/x) + cos^-1{√(x² - 225)/x}= π/2

so, 8/x = √(x² - 225)/x

8 = √(x² - 225)

taking square both sides,

64 = x² - 225

x² = 289 => 17²

x = ±17

hence, x = ±17