Question

Solve the following equation for x: $tan^{-1}(\frac{x - 1}{x - 2}) + tan^{-1}(\frac{x + 1}{x + 2}) = \frac{\pi}{4}$.

Answer 1

Answer:

The answer to this question is  " x = 1/√2 " and " x = -1/√2 "

Explanation:

According to the given condition, we have to solve this equation for   " x ".

⇒ We have to find the Value(s) of " x ".

This question involves inverse trigonometric functions.

We need to remeber one thing.

Only one-to-one functions have inverse functions.

The Trigonometric Functions are not one-to-one functions.

But we can make them one-to-one functions by restricting their domain.

Kindly see the attachment for detailed answer.

I hope it will help you.