Question

 solve the following equation in the picture below

Answer 1

first lcm the left and side and cross multiply both the sides u will get 
18y +12 =14y -6 
18y -14y = -6 -12
4y =-18
y= -9/2 

Answer 2

$\frac{6y+2}{2} + 1 = \frac{7y-3}{3}$

⇒$\frac{6y+2 +2}{2}= \frac{7y-3}{3}$

⇒$\frac{2(3y+2)}{2}= \frac{7y-3}{3}$

⇒${3y+2}= \frac{7y-3}{3}$

⇒${3(3y+2)}= {7y-3}$

⇒$9y+6 =7y - 3$

⇒$2y = -9$

⇒$y=\frac{-9}{2}$