Question

solve the following equation in the picture below

Answer 1

The common denominator is 6.

So we will multiply the first fraction with 3
the 1 will be multiplied with 6
and the result with 2.

In this way we will get rid of the fraction.
3(6y+1)+1*6=2(7y-3)
18y+3+6=14y-6
18y+9=14y-6
18y-14y=-6-9
4y=-15
y=-15/4

Answer 2

$\frac{6y+1}{2} + 1 = \frac{7y-3}{3}$

⇒$\frac{6y+1 +2}{2}= \frac{7y-3}{3}$

⇒$\frac{6y+3}{2}= \frac{7y-3}{3}$

⇒${3(6y+3)}= {2(7y-3)}$

⇒$18y+9 =14y - 6$

⇒$4y = -15$

⇒$y=\frac{-15}{4}$