Question

Solve the following equation simultaneously


X-Y=3
X^2+Y^2=29

Answer 1

Answer:

Explanation: Since you have both x2+y2=29 and y−x=3 , y−x=3→y=x+3 and we have y2=x2+6x+9. Since x2+y2=29 , substitute the expression for y2 into this: 2x2+6x+9=29 , so 2x2+6x−20=0 .

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Answer 2

Step by step explanation: